\(\begin{alignat}{1}
If \(X\) is path-connected, the isomorphism type of \(\pi_1(X,x_0)\) is independent of the basepoint \(x_0\), and we write simply \(\pi_1(X)\).
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func (opt *Option) Unknown() error
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Dublin, Helsinki, Stockholm and Tallinn among port cities more choked by sulphur oxides from ferries, analysis shows
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